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  #1  
Old 01-17-2007, 11:12 AM
J-Factor is offline J-Factor
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Sat (test) Question

This is a math question for you all math people out there.


The sum of the positive odd integers less than 50 is
suntracted from the sum of the positive even integers less than or equal to 50. What is the resulting difference?

A: 0
B: 25
C: 50
D: 100
E: 200

PS: I got the answer, post your answer and I'll tell you if you get it right or not.
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  #2  
Old 01-17-2007, 02:22 PM
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0?

Chris
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  #3  
Old 01-17-2007, 02:59 PM
Luckz is offline Luckz

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it just ends up being 1+1+1+1 til you get to 25.

Answer B
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  #4  
Old 01-17-2007, 03:29 PM
J-Factor is offline J-Factor
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Answer: B = Luckz niice job.

Explanation:
The sum of the positive odd integers less than 50 is 1 + 3 + 5 + --- + 45 + 47 + 49, and the sum of the postive even integers less then or equal to 50 is 2 + 4 + 6 + --- + 46 + 48 +50. When the first sum is suntracted from the second, the terms can be regrouped to form ( 2 - 1) + (4 - 3) + --- + (48 - 47) + (50 - 49), which is just 1 + 1 +1 + --- + 1 where there are 25 ones. Therefore, the correcr answer is 25.
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  #5  
Old 01-17-2007, 03:40 PM
J-Factor is offline J-Factor
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Another SAT TEST QUESTION

The length of rectangle S is 20 percent longer than the length of rectangle R, and the width of rectangle S is 20 percent shorter than the width of rectangle R. The area of rectangle S is?

A: 20% greater than the area of rectangle R
B: 4% greater than the area of rectangle R
C: equal to the area of rectangle R
D: 4% less than than the area of rectangle R
E: 20% less than the area of rectangle R

PS: I got the answer, post your answer and I'll tell you if you get it right or not.
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  #6  
Old 01-17-2007, 04:04 PM
Chrispy is offline Chrispy

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C and/or E?

Mostly C...

Chris
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  #7  
Old 01-17-2007, 06:55 PM
J-Factor is offline J-Factor
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Try again.
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  #8  
Old 01-17-2007, 07:14 PM
Lakie is offline Lakie

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D?
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  #9  
Old 01-17-2007, 07:23 PM
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Quote:
Originally posted by Mike
D?
I've got a feeling he's right lol.

Chris
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  #10  
Old 01-17-2007, 07:49 PM
Grenademan is offline Grenademan
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Nooooo! Not maths! GET AWAY FROM ME!
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  #11  
Old 01-17-2007, 07:56 PM
J-Factor is offline J-Factor
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Correct Mike nice job.

Explanation:
Represent the length and width of rectangle R as x and y. Then the area of R is xy. the length of rectangle S is 20% longer than x, which is x + 0.20x, or 1.2x. Similarly, the width of S is y - 0.20y, or 0.8y. The area of S is (1.2x) (0.8y), which simplifies to 0.96xy. From this it follows that the area of rectangle S is 4% less than the area of rectangle R.
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  #12  
Old 01-18-2007, 01:06 PM
VooDoo- is offline VooDoo-
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i got an SAT question

Sally has two dogs, Bob has five fish, and Chris has 3 parrots. How many pounds of bacon does Charlie need to buy on Saturday?
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  #13  
Old 01-18-2007, 02:05 PM
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who the fudge is charlie? hehe
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  #14  
Old 01-18-2007, 02:40 PM
J-Factor is offline J-Factor
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lol, yea really?
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  #15  
Old 01-19-2007, 12:47 AM
Purple Kush is offline Purple Kush
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ok i got a math problem for you guys......if you can have 3 seperate numbers, and each number can be any number between 1 and 60 how many different number variations can you have?
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Old 01-19-2007, 02:44 AM
Hellfighter is offline Hellfighter
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Quote:
Originally posted by VooDoo-
i got an SAT question

Sally has two dogs, Bob has five fish, and Chris has 3 parrots. How many pounds of bacon does Charlie need to buy on Saturday?
he don't need to buy any at all.

i mean why buy pork when there a whole world of beef to buy out there. beefy.

Eggs, beef, coffee, fry potato's to eat in the morning.
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  #17  
Old 01-19-2007, 02:53 AM
Hellfighter is offline Hellfighter
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Quote:
Originally posted by Purple Kush
ok i got a math problem for you guys......if you can have 3 seperate numbers, and each number can be any number between 1 and 60 how many different number variations can you have?
60x60=3600
-60x-60=-3600

720000 ways plus and minus or

-3600
0
+3600

total 720.000 ways

and there the infinite number system, i not even going to go there it would be unlimited numbers to count up to
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Last edited by Hellfighter; 01-19-2007 at 03:00 AM.
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  #18  
Old 01-19-2007, 10:09 AM
Capers is offline Capers
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Quote:
Originally posted by Purple Kush
ok i got a math problem for you guys......if you can have 3 seperate numbers, and each number can be any number between 1 and 60 how many different number variations can you have?
Basic Multiplication Rule:

60 * 59 * 58

=

205320 different combinations
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